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ServiceNow Scripting Question – Array

Array A = [1,2,3,4,5], Print in reverse order.

Method 1:

var numbers_array = [1, 2, 3, 4, 5];

gs.info("Original Array: "+numbers_array);

numbers_array.reverse();

gs.info("Reversed Array: "+numbers_array);

Method 2:

var original_array = [1, 2, 3, 4];

var reversed_array = [];

gs.info("Original Array: "+original_array);

for (var i = original_array.length - 1; i >= 0; i--) {
    reversed_array.push(original_array[i]);
}

gs.info("Reversed Array: "+reversed_array);

Array A = [1,3,5,7] & B = [2,3,4,5,6,9]. Intersection of two Arrays.

var first_array = [1, 3, 5, 7];
var second_array = [2, 3, 4, 5, 6, 9];

	var new_array = [];
	for (var i = 0; i < first_array.length; i++) {
		for (var j = 0; j < second_array.length; j++) {
			if (first_array[i] === second_array[j]) {
				new_array.push(first_array[i]);
			}
		}
	}



gs.info("Array obtained is : "+new_array);

Array A = [1,3,5,7] & B = [2,3,4,5,6,9]. Union of two Arrays.

var first_array = [1, 3, 5, 7];
var second_array = [2, 3, 4, 5, 6, 9];

var new_array = first_array.concat(second_array)


gs.info("Array is : "+new_array);

Array A= [1,3,5,7,2,3,4,5,6,9], Remove duplicates.

var new_array= [1,3,5,7,2,3,4,5,6,9]
function removeDuplicates(arr) {
    var unique = [];
    for (var i = 0; i < arr.length; i++) {
        if (unique.indexOf(arr[i]) === -1) {
            unique.push(arr[i]);
        }
    }
    return unique;
}
gs.info("Unique Array "+removeDuplicates(new_array));

Array A = [1,3,5,7,2,3,4,5,6,9], Sorting an Array.

var new_array= [1,3,5,7,2,3,4,5,6,9];
gs.info("Array obtained is : "+new_array.sort());

Array A = [1,2,3] & B = [3,4,5]. Find out two elements which product is 6.

var array_first = [1,2,3];
var array_second = [3,4,5];
var product = 6;
for(var i=0; i<array_first.length;i++){
	for(var k=0; k<array_second.length; k++){
		if(array_first[i]*array_second[k] == product){
			gs.info('Position: '+i+'--'+k+' Element '+array_first[i]+'--'+array_second[k]);
			break;
		}
	}
}

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